"use strict";

Object.defineProperty(exports, "__esModule", {
  value: true
});
exports.findListDiffIndex = findListDiffIndex;
exports.getIndexByStartLoc = getIndexByStartLoc;
/**
 * Get index with specific start index one by one. e.g.
 * min: 3, max: 9, start: 6
 *
 * Return index is:
 * [0]: 6
 * [1]: 7
 * [2]: 5
 * [3]: 8
 * [4]: 4
 * [5]: 9
 * [6]: 3
 */
function getIndexByStartLoc(min, max, start, index) {
  const beforeCount = start - min;
  const afterCount = max - start;
  const balanceCount = Math.min(beforeCount, afterCount) * 2;
  // Balance
  if (index <= balanceCount) {
    const stepIndex = Math.floor(index / 2);
    if (index % 2) {
      return start + stepIndex + 1;
    }
    return start - stepIndex;
  }
  // One is out of range
  if (beforeCount > afterCount) {
    return start - (index - afterCount);
  }
  return start + (index - beforeCount);
}
/**
 * We assume that 2 list has only 1 item diff and others keeping the order.
 * So we can use dichotomy algorithm to find changed one.
 */
function findListDiffIndex(originList, targetList, getKey) {
  const originLen = originList.length;
  const targetLen = targetList.length;
  let shortList;
  let longList;
  if (originLen === 0 && targetLen === 0) {
    return null;
  }
  if (originLen < targetLen) {
    shortList = originList;
    longList = targetList;
  } else {
    shortList = targetList;
    longList = originList;
  }
  const notExistKey = {
    __EMPTY_ITEM__: true
  };
  function getItemKey(item) {
    if (item !== undefined) {
      return getKey(item);
    }
    return notExistKey;
  }
  // Loop to find diff one
  let diffIndex = null;
  let multiple = Math.abs(originLen - targetLen) !== 1;
  for (let i = 0; i < longList.length; i += 1) {
    const shortKey = getItemKey(shortList[i]);
    const longKey = getItemKey(longList[i]);
    if (shortKey !== longKey) {
      diffIndex = i;
      multiple = multiple || shortKey !== getItemKey(longList[i + 1]);
      break;
    }
  }
  return diffIndex === null ? null : {
    index: diffIndex,
    multiple
  };
}