34 lines
774 B
Python
34 lines
774 B
Python
"""健康等级工具函数
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根据评分获取健康等级及中文标签，供 scoring_service / geo_diagnosis 等模块复用。
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"""
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def get_health_level(score: float) -> str:
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"""
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根据评分获取健康等级
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80+ -> excellent (优秀/绿)
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60-79 -> good (良好/黄)
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40-59 -> pass (及格/橙)
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<40 -> danger (危险/红)
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"""
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if score >= 80:
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return "excellent"
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if score >= 60:
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return "good"
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if score >= 40:
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return "pass"
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return "danger"
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def get_health_level_label(level: str) -> str:
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"""获取健康等级中文标签"""
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labels = {
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"excellent": "优秀",
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"good": "良好",
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"pass": "及格",
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"danger": "危险",
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}
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return labels.get(level, "未知")
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